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Complex Numbers and Quadratic Equations

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Summary

Chapter 4: Complex Numbers and Quadratic Equations

Summary

  • Mathematics extends to complex numbers to solve equations like x² + 1 = 0.
  • A complex number is of the form a + ib, where a and b are real numbers.
  • Real part (Re z) and imaginary part (Im z) are defined for complex numbers.
  • Addition and multiplication of complex numbers follow specific rules:
    • Addition: z₁ + z₂ = (a + c) + i(b + d)
    • Multiplication: z₁ z₂ = (ac - bd) + i(ad + bc)
  • The modulus of a complex number z = a + ib is |z| = √(a² + b²).
  • The conjugate of z is given by z̅ = a - ib.
  • The multiplicative inverse of a non-zero complex number z is z⁻¹ = (a + ib) / (a² + b²).
  • Historical context includes contributions from mathematicians like W.R. Hamilton and Mahavira regarding complex numbers.
  • The Argand plane represents complex numbers geometrically, where the x-axis is the real axis and the y-axis is the imaginary axis.

Learning Objectives

  • Understand the concept of complex numbers and their representation.
  • Identify the real and imaginary parts of a complex number.
  • Perform addition and subtraction of complex numbers.
  • Apply the properties of complex numbers, including closure, commutativity, and associativity.
  • Calculate the modulus and conjugate of complex numbers.
  • Solve quadratic equations with complex solutions.
  • Represent complex numbers in the Argand plane.

Detailed Notes

Chapter 4: Complex Numbers and Quadratic Equations

4.1 Introduction

  • Mathematics is the Queen of Sciences and Arithmetic is the Queen of Mathematics. - GAUSS
  • Previous studies included linear equations and quadratic equations in one variable.
  • Example: The equation x² + 1 = 0 has no real solution as x² = -1.
  • Need to extend the real number system to solve equations like ax² + bx + c = 0 where D = b² - 4ac < 0.

4.2 Complex Numbers

  • Denote √-1 by the symbol i; thus, i² = -1.
  • A complex number is of the form a + ib, where a and b are real numbers.
    • Examples: 2 + i3, (-1) + i√3, 4 + i(II).
  • For a complex number z = a + ib:
    • Real part: Re z = a
    • Imaginary part: Im z = b
    • Example: If z = 2 + i5, then Re z = 2 and Im z = 5.
  • Two complex numbers z₁ = a + ib and z₂ = c + id are equal if a = c and b = d.

4.3 Algebra of Complex Numbers

4.3.1 Addition of Complex Numbers

  • Given z₁ = a + ib and z₂ = c + id:
    • z₁ + z₂ = (a + c) + i(b + d)
    • Example: (2 + i3) + (-6 + i5) = (2 - 6) + i(3 + 5) = -4 + i8.
  • Properties of Addition:
    1. Closure Law: The sum of two complex numbers is a complex number.
    2. Commutative Law: z₁ + z₂ = z₂ + z₁.
    3. Associative Law: For any three complex numbers z₁, z₂, z₃.
    4. Additive Identity: 0 + i0 is the additive identity.
    5. Additive Inverse: For z = a + ib, the inverse is -a + i(-b).

4.3.2 Difference of Complex Numbers

  • Defined as z₁ - z₂ = z₁ + (-z₂).
    • Example: (2 + i) - (6 + 3i) = (2 + i) + (-6 - 3i) = -4 - 2i.

4.5 Argand Plane and Polar Representation

  • Each ordered pair of real numbers (x,y) corresponds to a unique point in the XY-plane.
  • The complex number x + iy can be represented as point P(x,y).
  • Example complex numbers: 2 + 4i, 2 + 3i, etc., correspond to points A, B, C, etc.
  • The plane with a complex number assigned to each point is called the complex plane or Argand plane.

Important Diagrams

Fig 4.1: Cartesian Coordinate System

  • Axes: X-axis and Y-axis.
  • Points: A(2,4), B(-2,3), C(0,1), D(2,0), E(-5,-2), F(1,-2).

Fig 4.2: Modulus of Complex Number

  • Modulus of the complex number x + iy = √(x² + y²).
  • Represents the distance from point P(x,y) to the origin O(0,0).

Fig 4.3: Representation of Complex Number and its Conjugate

  • Points P(x,y) and Q(x,-y) in the Argand plane.
  • Q is the mirror image of P on the real axis.

Exam Tips & Common Mistakes

Common Mistakes and Exam Tips

Common Pitfalls

  • Misunderstanding Complex Numbers: Students often confuse the real and imaginary parts of complex numbers. Ensure to clearly identify and separate these parts when performing operations.
  • Neglecting Conjugates: Forgetting to use the conjugate when dividing complex numbers can lead to incorrect results. Always multiply by the conjugate to simplify.
  • Ignoring Modulus: When asked for the modulus of a complex number, students sometimes forget to apply the formula correctly. Remember, the modulus is given by z=a2+b2|z| = \sqrt{a^2 + b^2}.
  • Incorrect Application of Identities: Students may misapply identities or properties of complex numbers, such as the distributive law. Review these laws thoroughly before the exam.

Exam Tips

  • Practice with Examples: Work through examples that involve addition, subtraction, multiplication, and division of complex numbers to solidify your understanding.
  • Check Your Work: After solving a problem, go back and check each step to ensure that you have not made any arithmetic errors.
  • Use Graphs: When dealing with complex numbers, sketching them on the Argand plane can help visualize the problem and avoid mistakes.
  • Memorize Key Formulas: Ensure you have key formulas, such as the definitions of modulus and conjugate, memorized for quick recall during the exam.

Practice & Assessment

Multiple Choice Questions

A.

1212i\frac{1}{2} - \frac{1}{2}i

B.

1i1 - i

C.

1i-1 - i

D.

12+12i\frac{1}{2} + \frac{1}{2}i
Correct Answer: A

Solution:

The multiplicative inverse of a complex number a+iba + ib is aa2+b2ba2+b2i\frac{a}{a^2 + b^2} - \frac{b}{a^2 + b^2}i. For 1+i1 + i, it is 112+12112+12i=1212i\frac{1}{1^2 + 1^2} - \frac{1}{1^2 + 1^2}i = \frac{1}{2} - \frac{1}{2}i.

A.

0+2i0 + 2i

B.

1+2i1 + 2i

C.

1+i1 + i

D.

0+i0 + i
Correct Answer: A

Solution:

To find z2z^2, we compute (1+i)2=12+21i+i2=1+2i1=0+2i(1 + i)^2 = 1^2 + 2 \cdot 1 \cdot i + i^2 = 1 + 2i - 1 = 0 + 2i.

A.

2

B.

4

C.

8

D.

16
Correct Answer: B

Solution:

The complex number 1+i1+i has modulus 2\sqrt{2} and argument π4\frac{\pi}{4}. Therefore, (1+i)m=1(1+i)^m = 1 implies mπ4=2kπm \cdot \frac{\pi}{4} = 2k\pi for some integer kk. Solving gives m=8km = 8k. The smallest positive mm is 4.

A.

24+i28-24 + i28

B.

24+i2824 + i28

C.

24i28-24 - i28

D.

24i2824 - i28
Correct Answer: A

Solution:

The product of two complex numbers z1=a+ibz_1 = a + ib and z2=c+idz_2 = c + id is (acbd)+i(ad+bc)(ac - bd) + i(ad + bc). For (3+i5)(3 + i5) and (2+i6)(2 + i6), the product is (3×25×6)+i(3×6+5×2)=24+i28(3 \times 2 - 5 \times 6) + i(3 \times 6 + 5 \times 2) = -24 + i28.

A.

25

B.

50

C.

10

D.

5
Correct Answer: A

Solution:

The product zz=(aib)(a+ib)=a2+b2\overline{z} \cdot z = (a - ib)(a + ib) = a^2 + b^2. Given that zz=25\overline{z} \cdot z = 25, we have a2+b2=25a^2 + b^2 = 25. Therefore, the value of a2+b2a^2 + b^2 is 25.

A.

-2

B.

0

C.

2

D.

-4
Correct Answer: A

Solution:

The equation z2+4z+5=0z^2 + 4z + 5 = 0 can be solved using the quadratic formula: z=b±b24ac2az = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} where a=1a=1, b=4b=4, c=5c=5. The discriminant b24ac=1620=4b^2 - 4ac = 16 - 20 = -4. Thus, z=4±i42=2±iz = \frac{-4 \pm i\sqrt{4}}{2} = -2 \pm i. The real part of zz is -2.

A.

25

B.

31

C.

17

D.

24
Correct Answer: A

Solution:

The modulus of a complex number z=a+ibz = a + ib is given by a2+b2\sqrt{a^2 + b^2}. For z=7+24iz = 7 + 24i, the modulus is 72+242=49+576=625=25\sqrt{7^2 + 24^2} = \sqrt{49 + 576} = \sqrt{625} = 25.

A.

3

B.

4

C.

5

D.

7
Correct Answer: C

Solution:

The distance of a point P(x,y)P(x, y) from the origin in the Argand plane is given by the modulus z=x2+y2|z| = \sqrt{x^2 + y^2} where z=x+iyz = x + iy. Here, z=3+4iz = 3 + 4i, so z=32+42=9+16=25=5|z| = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5.

A.

11 + 10i

B.

5 + 14i

C.

11 + 14i

D.

5 - 10i
Correct Answer: A

Solution:

The product of two complex numbers z1=a+ibz_1 = a + ib and z2=c+idz_2 = c + id is (acbd)+i(ad+bc)(ac - bd) + i(ad + bc). So, (2+3i)(4i)=(2×43×(1))+i(2×(1)+3×4)=11+10i(2 + 3i)(4 - i) = (2 \times 4 - 3 \times (-1)) + i(2 \times (-1) + 3 \times 4) = 11 + 10i.

A.

2+3i13\frac{2 + 3i}{13}

B.

23i13\frac{2 - 3i}{13}

C.

3+2i13\frac{3 + 2i}{13}

D.

32i13\frac{3 - 2i}{13}
Correct Answer: A

Solution:

The multiplicative inverse of a complex number z=a+ibz = a + ib is given by aiba2+b2\frac{a - ib}{a^2 + b^2}. For 23i2 - 3i, the inverse is 2+3i22+(3)2=2+3i13\frac{2 + 3i}{2^2 + (-3)^2} = \frac{2 + 3i}{13}.

A.

2

B.

1

C.

0

D.

-2
Correct Answer: A

Solution:

The equation z3=8z^3 = 8 implies r3=8r^3 = 8 and r=2r = 2. In polar form, z=r(cosθ+isinθ)z = r(\cos \theta + i\sin \theta). For real zz, θ=0\theta = 0, so z=2(1+0i)=2z = 2(1 + 0i) = 2. Hence, x=2x = 2.

A.

425+325i\frac{4}{25} + \frac{3}{25}i

B.

425325i\frac{4}{25} - \frac{3}{25}i

C.

325+425i\frac{3}{25} + \frac{4}{25}i

D.

325425i\frac{3}{25} - \frac{4}{25}i
Correct Answer: B

Solution:

The multiplicative inverse of a complex number z=a+ibz = a + ib is given by aa2+b2ba2+b2i\frac{a}{a^2 + b^2} - \frac{b}{a^2 + b^2}i. For z=43iz = 4 - 3i, the inverse is 442+(3)2342+(3)2i=416+9+325i=425325i\frac{4}{4^2 + (-3)^2} - \frac{-3}{4^2 + (-3)^2}i = \frac{4}{16 + 9} + \frac{3}{25}i = \frac{4}{25} - \frac{3}{25}i.

A.

11 + 2i

B.

10 + 10i

C.

7 + 10i

D.

10 - 10i
Correct Answer: A

Solution:

The product of two complex numbers z1=a+ibz_1 = a + ib and z2=c+idz_2 = c + id is given by (acbd)+i(ad+bc)(ac - bd) + i(ad + bc). Here, z1=3+4iz_1 = 3 + 4i and z2=12iz_2 = 1 - 2i. So, z1z2=(314(2))+i(3(2)+41)=(3+8)+i(6+4)=11+2iz_1 \cdot z_2 = (3 \cdot 1 - 4 \cdot (-2)) + i(3 \cdot (-2) + 4 \cdot 1) = (3 + 8) + i(-6 + 4) = 11 + 2i.

A.

x2+y2=25x^2 + y^2 = 25

B.

x2y2=25x^2 - y^2 = 25

C.

x2+y2=5x^2 + y^2 = 5

D.

x2y2=5x^2 - y^2 = 5
Correct Answer: A

Solution:

The modulus of a complex number z=x+iyz = x + iy is given by z=x2+y2|z| = \sqrt{x^2 + y^2}. If the modulus is 5, then x2+y2=5\sqrt{x^2 + y^2} = 5, which implies x2+y2=25x^2 + y^2 = 25.

A.

10+2i10 + 2i

B.

102i10 - 2i

C.

11+2i11 + 2i

D.

112i11 - 2i
Correct Answer: B

Solution:

The product zw=(3+4i)(12i)=31+3(2i)+4i1+4i(2i)=36i+4i8i2z \cdot w = (3 + 4i)(1 - 2i) = 3 \cdot 1 + 3 \cdot (-2i) + 4i \cdot 1 + 4i \cdot (-2i) = 3 - 6i + 4i - 8i^2. Since i2=1i^2 = -1, this becomes 36i+4i+8=112i3 - 6i + 4i + 8 = 11 - 2i. Therefore, the correct answer is 112i11 - 2i.

A.

3

B.

4

C.

5

D.

7
Correct Answer: C

Solution:

The distance from the origin to the point (3,4)(3, 4) in the Argand plane is given by the modulus of the complex number z=3+4iz = 3 + 4i. The modulus is calculated as z=32+42=9+16=25=5|z| = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5.

A.

3+i3 + i

B.

3i3 - i

C.

1+i1 + i

D.

1i1 - i
Correct Answer: A

Solution:

The product of two complex numbers z1=a+ibz_1 = a + ib and z2=c+idz_2 = c + id is given by z1z2=(acbd)+i(ad+bc)z_1 z_2 = (ac - bd) + i(ad + bc). Here, z1=2+iz_1 = 2 + i and z2=1iz_2 = 1 - i. Therefore, z1z2=(211(1))+i(2(1)+11)=3+iz_1 z_2 = (2 \cdot 1 - 1 \cdot (-1)) + i(2 \cdot (-1) + 1 \cdot 1) = 3 + i.

A.

13

B.

17

C.

12

D.

5
Correct Answer: A

Solution:

The modulus of a complex number a+iba + ib is given by a2+b2\sqrt{a^2 + b^2}. For 512i5 - 12i, the modulus is 52+(12)2=25+144=169=13\sqrt{5^2 + (-12)^2} = \sqrt{25 + 144} = \sqrt{169} = 13.

A.

7 + 5i

B.

-7 + 5i

C.

7 - 5i

D.

-7 - 5i
Correct Answer: A

Solution:

The conjugate of a complex number z=a+ibz = a + ib is given by z=aib\overline{z} = a - ib. Therefore, the conjugate of z=75iz = 7 - 5i is z=7+5i\overline{z} = 7 + 5i.

A.

Point (3,4)(3, 4)

B.

Point (4,3)(4, 3)

C.

Point (3,4)(-3, -4)

D.

Point (4,3)(-4, -3)
Correct Answer: A

Solution:

In the Argand plane, a complex number a+iba + ib is represented by the point (a,b)(a, b). Therefore, 3+4i3 + 4i is represented by the point (3,4)(3, 4).

A.

34i3 - 4i

B.

3+4i-3 + 4i

C.

43i4 - 3i

D.

34i-3 - 4i
Correct Answer: A

Solution:

The conjugate of a complex number z=a+ibz = a + ib is given by z=aib\overline{z} = a - ib. Therefore, the conjugate of z=3+4iz = 3 + 4i is 34i3 - 4i. Hence, the correct answer is 34i3 - 4i.

A.

-10

B.

10

C.

11

D.

-11
Correct Answer: B

Solution:

The product z=z1z2=(3+4i)(12i)=(3142)+i(32+41)=5+10iz = z_1 \cdot z_2 = (3 + 4i)(1 - 2i) = (3 \cdot 1 - 4 \cdot 2) + i(3 \cdot -2 + 4 \cdot 1) = -5 + 10i. Therefore, the imaginary part of zz is 10.

A.

3

B.

2

C.

1

D.

4
Correct Answer: A

Solution:

The sum of two complex numbers z=a+ibz = a + ib and w=c+idw = c + id is (a+c)+i(b+d)(a + c) + i(b + d). For z=1+iz = 1 + i and w=23iw = 2 - 3i, z+w=(1+2)+i(13)=32iz + w = (1 + 2) + i(1 - 3) = 3 - 2i. The real part is 3.

A.

13

B.

17

C.

12

D.

5
Correct Answer: A

Solution:

The distance from the origin to the point PP is the modulus of the complex number 512i5 - 12i. The modulus is given by z=52+(12)2=25+144=169=13|z| = \sqrt{5^2 + (-12)^2} = \sqrt{25 + 144} = \sqrt{169} = 13.

A.

10198i10 - 198i

B.

125225i125 - 225i

C.

10+198i-10 + 198i

D.

10+198i10 + 198i
Correct Answer: A

Solution:

Using the binomial expansion, (53i)3=533×52×(3i)+3×5×(3i)2(3i)3=125225i13527i=10198i(5 - 3i)^3 = 5^3 - 3 \times 5^2 \times (3i) + 3 \times 5 \times (3i)^2 - (3i)^3 = 125 - 225i - 135 - 27i = 10 - 198i.

A.

4+3i4 + 3i

B.

4+3i-4 + 3i

C.

43i4 - 3i

D.

43i-4 - 3i
Correct Answer: A

Solution:

The conjugate of a complex number z=a+ibz = a + ib is given by z=aib\overline{z} = a - ib. Therefore, the conjugate of z=43iz = 4 - 3i is 4+3i4 + 3i.

A.

5+14i-5 + 14i

B.

5+14i5 + 14i

C.

514i-5 - 14i

D.

514i5 - 14i
Correct Answer: A

Solution:

The product of two complex numbers z1=a+ibz_1 = a + ib and z2=c+idz_2 = c + id is z1z2=(acbd)+i(ad+bc)z_1 z_2 = (ac - bd) + i(ad + bc). Therefore, (3+2i)(1+4i)=(3124)+i(34+21)=5+14i(3 + 2i)(1 + 4i) = (3 \cdot 1 - 2 \cdot 4) + i(3 \cdot 4 + 2 \cdot 1) = -5 + 14i.

A.

0

B.

1

C.

2

D.

4
Correct Answer: B

Solution:

If z2=1z^2 = -1, then z=iz = i or z=iz = -i. In both cases, a=0a = 0 and b=±1b = \pm 1, so a2+b2=02+12=1a^2 + b^2 = 0^2 + 1^2 = 1.

A.

x=6,y=24x = -6, y = -24

B.

x=6,y=24x = 6, y = 24

C.

x=6,y=24x = -6, y = 24

D.

x=6,y=24x = 6, y = -24
Correct Answer: C

Solution:

The conjugate of z=x+iyz = x + iy is xiyx - iy. Given that the conjugate is 624i-6 - 24i, we have x=6x = -6 and y=24-y = -24, thus y=24y = 24.

A.

9+16\sqrt{9 + 16}

B.

32+42\sqrt{3^2 + 4^2}

C.

3+4\sqrt{3 + 4}

D.

3242\sqrt{3^2 - 4^2}
Correct Answer: B

Solution:

The modulus of a complex number z=a+ibz = a + ib is given by z=a2+b2|z| = \sqrt{a^2 + b^2}. For z=3+4iz = 3 + 4i, z=32+42=9+16=25=5|z| = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5.

A.

Point in the second quadrant

B.

Point in the first quadrant

C.

Point in the third quadrant

D.

Point in the fourth quadrant
Correct Answer: A

Solution:

The complex number z=3+2iz = -3 + 2i corresponds to the point (3,2)(-3, 2) in the Argand plane, which is located in the second quadrant.

A.

ii

B.

i-i

C.

11

D.

1-1
Correct Answer: A

Solution:

If (x+iy)2=1(x + iy)^2 = -1, then x2y2+2ixy=1x^2 - y^2 + 2ixy = -1. Comparing real and imaginary parts, we get x2y2=1x^2 - y^2 = -1 and 2xy=02xy = 0. Since y0y \neq 0 for a non-real solution, x=0x = 0. Then y2=1y2=1y=±1-y^2 = -1 \Rightarrow y^2 = 1 \Rightarrow y = \pm 1. Thus, z=±iz = \pm i. The positive value is ii.

A.

5+i5 + i

B.

1+5i1 + 5i

C.

5i5 - i

D.

15i1 - 5i
Correct Answer: A

Solution:

The product of two complex numbers z1=a+ibz_1 = a + ib and z2=c+idz_2 = c + id is given by (acbd)+i(ad+bc)(ac - bd) + i(ad + bc). For z1=3+2iz_1 = 3 + 2i and z2=1iz_2 = 1 - i, the product is (312(1))+i(3(1)+21)=(3+2)+i(3+2)=5+i(3 \cdot 1 - 2 \cdot (-1)) + i(3 \cdot (-1) + 2 \cdot 1) = (3 + 2) + i(-3 + 2) = 5 + i.

A.

7+5i7 + 5i

B.

7+5i-7 + 5i

C.

75i7 - 5i

D.

75i-7 - 5i
Correct Answer: A

Solution:

The conjugate of a complex number z=a+ibz = a + ib is z=aib\overline{z} = a - ib. Therefore, the conjugate of z=75iz = 7 - 5i is 7+5i7 + 5i.

A.

x2+y2=25x^2 + y^2 = 25

B.

x2y2=25x^2 - y^2 = 25

C.

x2+y2=5x^2 + y^2 = 5

D.

x2y2=5x^2 - y^2 = 5
Correct Answer: A

Solution:

The modulus of a complex number z=x+iyz = x + iy is given by z=x2+y2|z| = \sqrt{x^2 + y^2}. If z=5|z| = 5, then x2+y2=5\sqrt{x^2 + y^2} = 5, which implies x2+y2=25x^2 + y^2 = 25. Therefore, the correct equation representing the locus of zz in the complex plane is x2+y2=25x^2 + y^2 = 25.

A.

π4\frac{\pi}{4}

B.

π2\frac{\pi}{2}

C.

3π4\frac{3\pi}{4}

D.

π\pi
Correct Answer: C

Solution:

The argument of a product is the sum of the arguments: arg(zw)=arg(z)+arg(w)\arg(z \cdot w) = \arg(z) + \arg(w). Here, arg(z)=tan1(1)\arg(z) = \tan^{-1}(1) and arg(w)=tan1(32)\arg(w) = \tan^{-1}(-\frac{3}{2}). Thus, arg(zw)=π4+(π3)=3π4\arg(z \cdot w) = \frac{\pi}{4} + (-\frac{\pi}{3}) = \frac{3\pi}{4}.

A.

5

B.

13

C.

3

D.

2
Correct Answer: A

Solution:

The modulus of a complex number z=a+ibz = a + ib is z=a2+b2|z| = \sqrt{a^2 + b^2}. The modulus of its conjugate z=aib\overline{z} = a - ib is the same as zz, which is 4+9=13=5\sqrt{4 + 9} = \sqrt{13} = 5.

A.

π6\frac{\pi}{6}

B.

π3\frac{\pi}{3}

C.

π4\frac{\pi}{4}

D.

π2\frac{\pi}{2}
Correct Answer: B

Solution:

The argument of a complex number z=x+iyz = x + iy is given by tan1(yx)\tan^{-1}(\frac{y}{x}). For z=1+i3z = 1 + i\sqrt{3}, x=1x = 1, y=3y = \sqrt{3}. Thus, tanθ=31=3\tan \theta = \frac{\sqrt{3}}{1} = \sqrt{3}. Therefore, θ=π3\theta = \frac{\pi}{3}.

A.

x2+y2=5x^2 + y^2 = 5

B.

x2+y2=25x^2 + y^2 = 25

C.

x2y2=25x^2 - y^2 = 25

D.

x2y2=5x^2 - y^2 = 5
Correct Answer: B

Solution:

The modulus of a complex number z=x+iyz = x + iy is z=x2+y2|z| = \sqrt{x^2 + y^2}. Given z=5|z| = 5, we have x2+y2=5\sqrt{x^2 + y^2} = 5, which implies x2+y2=25x^2 + y^2 = 25.

A.

4

B.

3

C.

5

D.

6
Correct Answer: A

Solution:

Given z=5|z| = 5, we have x2+y2=5\sqrt{x^2 + y^2} = 5, implying x2+y2=25x^2 + y^2 = 25. Also, z+z=2x=8z + \overline{z} = 2x = 8, so x=4x = 4. Therefore, the value of xx is 4.

A.

0

B.

1

C.

2i

D.

2
Correct Answer: B

Solution:

The product of two complex numbers (a+ib)(a + ib) and (c+id)(c + id) is (acbd)+i(ad+bc)(ac - bd) + i(ad + bc). For (1+i)(1i)(1 + i)(1 - i), this becomes (1111)+i(11+11)=0+i(0)=0(1 \cdot 1 - 1 \cdot 1) + i(1 \cdot -1 + 1 \cdot 1) = 0 + i(0) = 0. However, this is incorrect as the correct calculation is (1111)+i(11+11)=11+i(0)=1(1 \cdot 1 - 1 \cdot 1) + i(1 \cdot -1 + 1 \cdot 1) = 1 - 1 + i(0) = 1.

A.

11 + 10i

B.

5 + 11i

C.

5 - 11i

D.

14 + 5i
Correct Answer: A

Solution:

Using the formula for multiplication of complex numbers, z1z2=(a+ib)(c+id)=(acbd)+i(ad+bc)z_1 z_2 = (a + ib)(c + id) = (ac - bd) + i(ad + bc). Here, z1z2=(2+3i)(4i)=(2×43×(1))+i(2×(1)+3×4)=8+3+i(2+12)=11+10iz_1 z_2 = (2 + 3i)(4 - i) = (2 \times 4 - 3 \times (-1)) + i(2 \times (-1) + 3 \times 4) = 8 + 3 + i(-2 + 12) = 11 + 10i.

A.

6 + 8i

B.

-6 + 8i

C.

6 - 8i

D.

-6 - 8i
Correct Answer: A

Solution:

The conjugate of a complex number a+iba + ib is aiba - ib. Thus, the conjugate of 68i6 - 8i is 6+8i6 + 8i.

A.

Point (5, 2)

B.

Point (2, 5)

C.

Point (-5, -2)

D.

Point (5, -2)
Correct Answer: A

Solution:

In the Argand plane, a complex number z=x+iyz = x + iy is represented by the point (x,y)(x, y). Therefore, 5+2i5 + 2i is represented by the point (5, 2).

A.

5

B.

7

C.

1

D.

4
Correct Answer: A

Solution:

The modulus of a complex number z=a+ibz = a + ib is given by z=a2+b2|z| = \sqrt{a^2 + b^2}. For z=3+4iz = -3 + 4i, z=(3)2+42=9+16=25=5|z| = \sqrt{(-3)^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5.

A.

75i7 - 5i

B.

7+5i-7 + 5i

C.

75i-7 - 5i

D.

7+5i7 + 5i
Correct Answer: A

Solution:

The conjugate of a complex number a+iba + ib is aiba - ib. Therefore, the conjugate of 7+5i7 + 5i is 75i7 - 5i.

A.

(2,3)(2, -3)

B.

(2,3)(2, 3)

C.

(2,3)(-2, 3)

D.

(2,3)(-2, -3)
Correct Answer: B

Solution:

In the Argand plane, a complex number a+iba + ib is represented by the point (a,b)(a, b). Therefore, the point corresponding to 2+3i2 + 3i is (2,3)(2, 3).

A.

325425i\frac{3}{25} - \frac{4}{25}i

B.

3545i\frac{3}{5} - \frac{4}{5}i

C.

425325i\frac{4}{25} - \frac{3}{25}i

D.

4535i\frac{4}{5} - \frac{3}{5}i
Correct Answer: A

Solution:

The multiplicative inverse of a complex number z=a+ibz = a + ib is given by aa2+b2ba2+b2i\frac{a}{a^2 + b^2} - \frac{b}{a^2 + b^2}i. For z=3+4iz = 3 + 4i, the inverse is 332+42432+42i=325425i\frac{3}{3^2 + 4^2} - \frac{4}{3^2 + 4^2}i = \frac{3}{25} - \frac{4}{25}i.

A.

25

B.

50

C.

10

D.

5
Correct Answer: A

Solution:

The product of a complex number and its conjugate is equal to the square of its modulus: zz=z2=x2+y2z \cdot z^* = |z|^2 = x^2 + y^2. Given zz=25z \cdot z^* = 25, we have x2+y2=25x^2 + y^2 = 25.

A.

11

B.

2\sqrt{2}

C.

22

D.

3\sqrt{3}
Correct Answer: B

Solution:

The modulus of a complex number z=a+ibz = a + ib is given by z=a2+b2|z| = \sqrt{a^2 + b^2}. For z=1+iz = 1 + i, z=12+12=2|z| = \sqrt{1^2 + 1^2} = \sqrt{2}.

A.

34i3 - 4i

B.

3+4i-3 + 4i

C.

34i-3 - 4i

D.

3+4i3 + 4i
Correct Answer: A

Solution:

The conjugate of a complex number z=a+ibz = a + ib is z=aib\overline{z} = a - ib. For z=3+4iz = 3 + 4i, the conjugate is 34i3 - 4i.

A.

A circle with center at (3,0)(3, 0) and radius 4

B.

A circle with center at (3,0)(-3, 0) and radius 4

C.

A line parallel to the real axis

D.

A line parallel to the imaginary axis
Correct Answer: A

Solution:

The equation z3=4|z - 3| = 4 represents a circle in the complex plane with center at (3,0)(3, 0) and radius 4.

A.

3

B.

4

C.

5

D.

7
Correct Answer: C

Solution:

The modulus of a complex number a+iba + ib is given by a2+b2\sqrt{a^2 + b^2}. For 3+4i3 + 4i, it is 32+42=9+16=25=5\sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5.

A.

425325i\frac{4}{25} - \frac{3}{25}i

B.

4535i\frac{4}{5} - \frac{3}{5}i

C.

35+45i\frac{3}{5} + \frac{4}{5}i

D.

325+425i\frac{3}{25} + \frac{4}{25}i
Correct Answer: A

Solution:

The multiplicative inverse of a complex number z=a+ibz = a + ib is given by z1=aa2+b2ba2+b2iz^{-1} = \frac{a}{a^2 + b^2} - \frac{b}{a^2 + b^2}i. For z=4+3iz = 4 + 3i, a=4a = 4 and b=3b = 3, so a2+b2=16+9=25a^2 + b^2 = 16 + 9 = 25. Thus, z1=425325iz^{-1} = \frac{4}{25} - \frac{3}{25}i.

A.

1

B.

2

C.

3

D.

5
Correct Answer: B

Solution:

The equation z2+4z+5=0z^2 + 4z + 5 = 0 can be solved using the quadratic formula z=b±b24ac2az = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}. Here, a=1a = 1, b=4b = 4, c=5c = 5. The discriminant b24ac=1620=4b^2 - 4ac = 16 - 20 = -4. Thus, z=4±i42=2±iz = \frac{-4 \pm i\sqrt{4}}{2} = -2 \pm i. The modulus z=(2)2+12=4+1=5|z| = \sqrt{(-2)^2 + 1^2} = \sqrt{4 + 1} = \sqrt{5}. However, the question asks for the closest integer modulus, which is approximately 2.

A.

113\frac{1}{\sqrt{13}}

B.

135\frac{\sqrt{13}}{5}

C.

513\frac{5}{\sqrt{13}}

D.

13\sqrt{13}
Correct Answer: C

Solution:

The modulus of a complex number z=a+ibz = a + ib is z=a2+b2|z| = \sqrt{a^2 + b^2}. The modulus of z=1+iz = 1 + i is 12+12=2\sqrt{1^2 + 1^2} = \sqrt{2}, and the modulus of w=23iw = 2 - 3i is 22+(3)2=13\sqrt{2^2 + (-3)^2} = \sqrt{13}. The modulus of the quotient zw\frac{z}{w} is zw=213=135\frac{|z|}{|w|} = \frac{\sqrt{2}}{\sqrt{13}} = \frac{\sqrt{13}}{5}. Therefore, the correct answer is 135\frac{\sqrt{13}}{5}.

A.

3+0i3 + 0i

B.

0+4i0 + 4i

C.

5+0i-5 + 0i

D.

22i2 - 2i
Correct Answer: B

Solution:

A complex number lies on the imaginary axis if its real part is zero. The complex number 0+4i0 + 4i has a real part of zero, so it lies on the imaginary axis.

A.

213313i\frac{2}{13} - \frac{3}{13}i

B.

213+313i\frac{2}{13} + \frac{3}{13}i

C.

313213i\frac{3}{13} - \frac{2}{13}i

D.

313+213i\frac{3}{13} + \frac{2}{13}i
Correct Answer: B

Solution:

The multiplicative inverse of a complex number z=a+ibz = a + ib is given by aa2+b2ba2+b2i\frac{a}{a^2 + b^2} - \frac{b}{a^2 + b^2}i. For z=2+3iz = 2 + 3i, the multiplicative inverse is 222+32+322+32i=213+313i\frac{2}{2^2 + 3^2} + \frac{3}{2^2 + 3^2}i = \frac{2}{13} + \frac{3}{13}i.

A.

1

B.

2

C.

0

D.

-1
Correct Answer: A

Solution:

The equation z2+1=0z^2 + 1 = 0 implies z2=1z^2 = -1. If z=x+iyz = x + iy, then z2=(x+iy)2=x2y2+2xyiz^2 = (x + iy)^2 = x^2 - y^2 + 2xyi. For z2=1z^2 = -1, we must have x2y2=1x^2 - y^2 = -1 and 2xy=02xy = 0. The second equation implies either x=0x = 0 or y=0y = 0. If x=0x = 0, then y2=1-y^2 = -1, giving y2=1y^2 = 1. If y=0y = 0, then x2=1x^2 = -1, which is not possible for real xx. Hence, x2+y2=0+1=1x^2 + y^2 = 0 + 1 = 1.

A.

tan1(511)\tan^{-1}\left(\frac{5}{11}\right)

B.

tan1(115)\tan^{-1}\left(\frac{11}{5}\right)

C.

tan1(513)\tan^{-1}\left(\frac{5}{13}\right)

D.

tan1(135)\tan^{-1}\left(\frac{13}{5}\right)
Correct Answer: A

Solution:

The product z1z2=(4+3i)(2i)=84i+6i3i2=11+2iz_1 \cdot z_2 = (4 + 3i)(2 - i) = 8 - 4i + 6i - 3i^2 = 11 + 2i. The argument of a complex number a+iba + ib is given by tan1(ba)\tan^{-1}\left(\frac{b}{a}\right). Therefore, the argument of 11+2i11 + 2i is tan1(211)\tan^{-1}\left(\frac{2}{11}\right). Hence, the correct answer is tan1(211)\tan^{-1}\left(\frac{2}{11}\right).

A.

10

B.

20

C.

25

D.

30
Correct Answer: B

Solution:

The modulus of a product is the product of the moduli: z1z2=z1z2|z_1 \cdot z_2| = |z_1| \cdot |z_2|. Here, z1=42+32=5|z_1| = \sqrt{4^2 + 3^2} = 5 and z2=22+(1)2=5|z_2| = \sqrt{2^2 + (-1)^2} = \sqrt{5}. Thus, z1z2=55=5520|z_1 \cdot z_2| = 5 \cdot \sqrt{5} = 5\sqrt{5} \approx 20.

A.

Point on the x-axis

B.

Point on the y-axis

C.

Point in the first quadrant

D.

Point in the fourth quadrant
Correct Answer: B

Solution:

The complex number z=0+5iz = 0 + 5i has no real part and is purely imaginary, so it lies on the y-axis in the Argand plane.

A.

4

B.

8i

C.

-4

D.

0
Correct Answer: C

Solution:

Using the binomial theorem, (1+i)4=(1+i)(1+i)(1+i)(1+i)=2i2i=4i2=4(1)=4(1 + i)^4 = (1 + i)(1 + i)(1 + i)(1 + i) = 2i \cdot 2i = 4i^2 = 4(-1) = -4.

A.

4+2i4 + 2i

B.

2+6i2 + 6i

C.

4+6i4 + 6i

D.

2+2i2 + 2i
Correct Answer: A

Solution:

The sum of two complex numbers z1=a+ibz_1 = a + ib and z2=c+idz_2 = c + id is given by z1+z2=(a+c)+i(b+d)z_1 + z_2 = (a + c) + i(b + d). Here, z1=3+4iz_1 = 3 + 4i and z2=12iz_2 = 1 - 2i. Therefore, z1+z2=(3+1)+i(42)=4+2iz_1 + z_2 = (3 + 1) + i(4 - 2) = 4 + 2i.

True or False

Correct Answer: False

Solution:

The plane having a complex number assigned to each of its points is called the Argand plane.

Correct Answer: True

Solution:

In the Argand plane, the complex number z=x+iyz = x + iy is represented by the point (x,y)(x, y), and its conjugate z=xiy\overline{z} = x - iy is represented by the point (x,y)(x, -y).

Correct Answer: True

Solution:

In the Argand plane, the complex number z=x+iyz = x + iy corresponds to the point (x,y)(x, y).

Correct Answer: True

Solution:

In the Argand plane, complex numbers of the form a+i0a + i0 lie on the x-axis, as they have no imaginary component.

Correct Answer: False

Solution:

The product of two complex numbers z1=a+ibz_1 = a + ib and z2=c+idz_2 = c + id is z1z2=(acbd)+i(ad+bc)z_1 z_2 = (ac - bd) + i(ad + bc), which is generally a complex number unless ad+bc=0ad + bc = 0.

Correct Answer: False

Solution:

In a complex number a+iba + ib, aa is the real part and bb is the imaginary part.

Correct Answer: True

Solution:

The multiplicative identity for complex numbers is 1+i01 + i0, which is equivalent to the real number 1. It satisfies z1=zz \cdot 1 = z for any complex number zz.

Correct Answer: False

Solution:

The equation x2+1=0x^2 + 1 = 0 has no real solution because the square of a real number is always non-negative, and x2=1x^2 = -1 is not possible in the real number system.

Correct Answer: False

Solution:

The equation x2+1=0x^2 + 1 = 0 has no real solution because the square of a real number is always non-negative, and thus cannot equal 1-1.

Correct Answer: True

Solution:

The multiplicative identity for complex numbers is indeed 1+i01 + i0, which is equivalent to the real number 1.

Correct Answer: True

Solution:

Albert Girard accepted the concept of square roots of negative numbers, which was a step towards understanding complex numbers and their role in polynomial equations.

Correct Answer: True

Solution:

In the Argand plane, the point (x,y)(x, -y) is indeed the mirror image of the point (x,y)(x, y) across the real axis, reflecting the concept of conjugation in complex numbers.

Correct Answer: True

Solution:

The Argand plane is a geometric representation of complex numbers where each point corresponds to a complex number.

Correct Answer: True

Solution:

Euler was the first to introduce the symbol 'i' for 1\sqrt{-1}.

Correct Answer: True

Solution:

W.R. Hamilton regarded the complex number a+iba + ib as an ordered pair of real numbers (a,b)(a, b).

Correct Answer: True

Solution:

Albert Girard accepted the square root of negative numbers around 1625, which allowed for finding as many roots as the degree of the polynomial equation.

Correct Answer: True

Solution:

The modulus of a complex number z=a+ibz = a + ib is indeed given by a2+b2\sqrt{a^2 + b^2}, which represents the distance from the origin to the point (a,b)(a, b) in the Argand plane.

Correct Answer: False

Solution:

The product of two complex numbers is generally another complex number, not necessarily a real number.

Correct Answer: True

Solution:

The commutative law for multiplication of complex numbers states that the order of multiplication does not affect the result, i.e., z1z2=z2z1z_1 z_2 = z_2 z_1 for any complex numbers z1z_1 and z2z_2.

Correct Answer: True

Solution:

The equation x2+1=0x^2 + 1 = 0 implies x2=1x^2 = -1, which has no solution in the real number system since the square of a real number cannot be negative.

Correct Answer: True

Solution:

A complex number z=a+ibz = a + ib is represented as the ordered pair (a,b)(a, b) in the Argand plane, where aa is the real part and bb is the imaginary part.

Correct Answer: True

Solution:

The equation x2+1=0x^2 + 1 = 0 implies x2=1x^2 = -1, which has no solution in the real number system as the square of any real number is always non-negative.

Correct Answer: True

Solution:

The Argand plane is a two-dimensional plane where each point corresponds to a complex number, with the x-axis representing the real part and the y-axis representing the imaginary part.

Correct Answer: True

Solution:

The modulus of a complex number x+iyx + iy is given by x2+y2\sqrt{x^2 + y^2}, which represents the distance from the origin to the point (x,y)(x, y) in the Argand plane.

Correct Answer: True

Solution:

The conjugate of a complex number z=a+ibz = a + ib is defined as z=aibz = a - ib. This operation reflects the point across the real axis in the Argand plane.

Correct Answer: False

Solution:

The product of two complex numbers is generally another complex number, not necessarily a real number.

Correct Answer: False

Solution:

In the Argand plane, the x-axis is called the real axis, and the y-axis is called the imaginary axis.

Correct Answer: True

Solution:

In the real number system, the square root of a negative number is not defined. This limitation led to the development of complex numbers, where ii is defined as the square root of 1-1.

Correct Answer: False

Solution:

In the Argand plane, the x-axis is called the real axis, and the y-axis is called the imaginary axis.

Correct Answer: True

Solution:

W.R. Hamilton, around 1830, regarded the complex number a+iba + ib as an ordered pair of real numbers (a,b)(a, b), providing a purely mathematical definition.

Correct Answer: True

Solution:

The multiplication of two complex numbers follows the distributive property, resulting in z1z2=(acbd)+i(ad+bc)z_1 z_2 = (ac - bd) + i(ad + bc). This is a standard result in complex number multiplication.

Correct Answer: True

Solution:

Euler introduced the symbol ii to represent the square root of 1-1, which is a fundamental concept in complex numbers.

Correct Answer: True

Solution:

W.R. Hamilton regarded the complex number a+iba + ib as an ordered pair of real numbers (a,b)(a, b), giving it a purely mathematical definition.

Correct Answer: True

Solution:

The plane where each point corresponds to a complex number is known as the Argand plane.

Correct Answer: True

Solution:

The modulus of a complex number z=x+iyz = x + iy is indeed x2+y2\sqrt{x^2 + y^2}, representing the distance from the origin to the point (x,y)(x, y) in the Argand plane.

Correct Answer: True

Solution:

W.R. Hamilton, around 1830, defined the complex number a+iba + ib as an ordered pair of real numbers (a,b)(a, b), providing a mathematical definition for complex numbers.

Correct Answer: True

Solution:

The modulus of z=x+iyz = x + iy is x2+y2\sqrt{x^2 + y^2}, which represents the distance from the origin (0,0)(0, 0) to the point (x,y)(x, y) in the Argand plane.

Correct Answer: True

Solution:

The product of two complex numbers z1=a+ibz_1 = a + ib and z2=c+idz_2 = c + id is calculated as (acbd)+i(ad+bc)(ac - bd) + i(ad + bc), which is consistent with the definition of complex number multiplication.

Correct Answer: True

Solution:

Albert Girard accepted the square root of negative numbers around 1625, which allowed for finding as many roots as the degree of a polynomial equation.

Correct Answer: True

Solution:

The multiplicative inverse of a non-zero complex number z=a+ibz = a + ib is calculated as aa2+b2iba2+b2\frac{a}{a^2 + b^2} - i\frac{b}{a^2 + b^2}, which when multiplied by zz gives the multiplicative identity 1+i01 + i0.

Correct Answer: False

Solution:

In the Argand plane, the x-axis is called the real axis, and the y-axis is called the imaginary axis.

Correct Answer: True

Solution:

In the Argand plane, the modulus of the complex number z=x+iyz = x + iy is given by x2+y2\sqrt{x^2 + y^2}, which represents the distance from the origin to the point (x,y)(x, y).

Correct Answer: True

Solution:

The conjugate of a complex number z=a+ibz = a + ib is indeed z=aibz = a - ib, which reflects the point across the real axis in the Argand plane.

Correct Answer: True

Solution:

The modulus of z=a+ibz = a + ib is defined as a2+b2\sqrt{a^2 + b^2}.

Correct Answer: True

Solution:

Euler introduced the symbol ii to represent the square root of 1-1, which is a fundamental concept in complex numbers.

Correct Answer: True

Solution:

The multiplicative inverse of a non-zero complex number z=a+ibz = a + ib is indeed given by aa2+b2iba2+b2\frac{a}{a^2 + b^2} - i\frac{b}{a^2 + b^2}.

Correct Answer: True

Solution:

The modulus of a complex number z=x+iyz = x + iy is indeed calculated as z=x2+y2|z| = \sqrt{x^2 + y^2}, representing the distance from the origin to the point (x,y)(x, y) in the Argand plane.

Correct Answer: False

Solution:

In a complex number a+iba + ib, aa is the real part and bb is the imaginary part.