Home

/

School

/

CBSE

/

Class 12 Science (PCM)

/

Mathematics Part 1

/

Continuity and Differentiability

CBSE Explorer

Continuity and Differentiability

AI Learning Assistant

I can help you understand Continuity and Differentiability better. Ask me anything!

Summarize the main points of Continuity and Differentiability.
What are the most important terms to remember here?
Explain this concept like I'm five.
Give me a quick 3-question practice quiz.

Summary

Chapter 5: Continuity and Differentiability

Summary

  • Continuation of differentiation study from Class XI.
  • Introduction of continuity and differentiability concepts.
  • Differentiation of inverse trigonometric functions.
  • Introduction of exponential and logarithmic functions.
  • Fundamental theorems in differential calculus.

Key Concepts

Continuity

  • A function is continuous at a point if the limit at that point equals the function's value.
  • Functions can be continuous on their entire domain.
  • Sum, difference, product, and quotient of continuous functions are also continuous.
  • Every differentiable function is continuous, but not vice versa.

Differentiability

  • The derivative of a function at a point is defined using limits:
    f(c)=limh0f(c+h)f(c)hf'(c) = \lim_{h \to 0} \frac{f(c+h) - f(c)}{h}

Exponential and Logarithmic Functions

  • Exponential functions grow rapidly; logarithmic functions are their inverses.
  • Logarithmic differentiation is used for functions of the form f(x)=[u(x)]v(x)f(x) = [u(x)]^{v(x)}.

Important Theorems

  • If ff and gg are continuous at cc, then:
    • f+gf + g is continuous at cc
    • fgf - g is continuous at cc
    • fgf \cdot g is continuous at cc
    • fg\frac{f}{g} is continuous at cc if g(c)0g(c) \neq 0

Exercises

  1. Prove that the function f(x)=5x3f(x) = 5x - 3 is continuous at specified points.
  2. Examine the continuity of various functions at given points.
  3. Differentiate functions using the chain rule and logarithmic differentiation.

Examples

  • Example of checking continuity at specific points.
  • Example of differentiating functions using various methods.

Learning Objectives

Learning Objectives

  • Understand the concepts of continuity and differentiability.
  • Differentiate polynomial, trigonometric, inverse trigonometric, exponential, and logarithmic functions.
  • Apply the chain rule for differentiation.
  • Identify and prove the continuity of various functions at specific points.
  • Utilize logarithmic differentiation for complex functions.
  • Explore the relationships between continuity and differentiability.
  • Recognize the importance of fundamental theorems in differential calculus.

Detailed Notes

Chapter 5: Continuity and Differentiability

5.1 Introduction

  • Continuation of differentiation study from Class XI.
  • Concepts introduced:
    • Continuity
    • Differentiability
    • Inverse trigonometric functions
    • Exponential and logarithmic functions
  • Fundamental theorems in differential calculus.

5.2 Continuity

  • Definition: A function is continuous at a point if the limit at that point equals the function's value.
  • Example: Function defined as:
    • f(x) = 1, if x ≤ 0
    • f(x) = 2, if x > 0
  • Graph Analysis: At x = 0, the function is not continuous.

Exercises

  1. Prove that f(x) = 5x - 3 is continuous at x = 0, x = -3, and x = 5.
  2. Examine continuity of f(x) = 2x² - 1 at x = 3.
  3. Examine the following functions for continuity:
    • (a) f(x) = 5
    • (b) f(x) = x
    • (c) f(x) = |x - 5|

5.3 Differentiability

  • Definition: The derivative of a real function at a point c is defined as:
    • lim (f(c+h) - f(c)) / h as h approaches 0.
  • Key Point: Every differentiable function is continuous, but not vice versa.

5.4 Exponential and Logarithmic Functions

  • Introduction to exponential functions and logarithmic functions.
  • Natural Exponential Function: y = e^x.
  • Logarithm Definition: For b > 1, log_b(a) = x if b^x = a.

Important Observations

  • Logarithm function is defined from positive real numbers to all real numbers.
  • Common logarithm (base 10) and natural logarithm (base e).

5.5 Logarithmic Differentiation

  • Technique for differentiating functions of the form f(x) = [u(x)]^v(x).
  • Both f(x) and u(x) must be positive for this technique.

5.6 Derivatives of Functions in Parametric Forms

  • Relationships between variables expressed via a third variable.
  • Example: x = a cos³(θ), y = a sin³(θ).

5.7 Miscellaneous Exercises

  • Differentiate various functions and find second-order derivatives.

Exam Tips & Common Mistakes

Common Mistakes and Exam Tips

Common Pitfalls

  • Misunderstanding Continuity: Students often confuse the conditions for a function to be continuous. Remember that a function must be defined at the point, and the limit must equal the function's value at that point.
  • Ignoring Piecewise Functions: When dealing with piecewise functions, ensure to check continuity at the boundaries where the definition changes.
  • Limit Calculation Errors: Be careful with limit calculations, especially at points of discontinuity. Ensure to evaluate both left-hand and right-hand limits.
  • Differentiability vs. Continuity: A common mistake is assuming that if a function is continuous, it is also differentiable. Remember that a function can be continuous but not differentiable at certain points.

Tips for Success

  • Practice with Examples: Work through various examples of continuity and differentiability to solidify understanding. Pay attention to the definitions and properties of functions.
  • Graph Functions: Sketching graphs can help visualize continuity and differentiability. Look for breaks, jumps, or corners in the graph that indicate discontinuity or non-differentiability.
  • Review Definitions: Regularly review the definitions of continuity and differentiability, and practice applying them to different types of functions.
  • Use Theorems: Familiarize yourself with fundamental theorems related to continuity and differentiability, as they can provide shortcuts in problem-solving.

Practice & Assessment

Multiple Choice Questions

A.

f(x)=sin(x)f(x) = \sin(x) and f(x)=cos(x)f'(x) = \cos(x)

B.

f(x)=cos(x)f(x) = \cos(x) and f(x)=sin(x)f'(x) = \sin(x)

C.

f(x)=tan(x)f(x) = \tan(x) and f(x)=sec(x)f'(x) = \sec(x)

D.

f(x)=xnf(x) = x^n and f(x)=nxn+1f'(x) = nx^{n+1}
Correct Answer: A

Solution:

The derivative of f(x)=sin(x)f(x) = \sin(x) is f(x)=cos(x)f'(x) = \cos(x), which is correctly matched. The other options are incorrect: f(x)=sin(x)f'(x) = -\sin(x) for cos(x)\cos(x), f(x)=sec2(x)f'(x) = \sec^2(x) for tan(x)\tan(x), and f(x)=nxn1f'(x) = nx^{n-1} for xnx^n.

A.

g(x)g(x) grows faster than f(x)f(x) for any nn.

B.

f(x)f(x) grows faster than g(x)g(x) for any nn.

C.

g(x)g(x) grows faster than f(x)f(x) only if nn is very large.

D.

f(x)f(x) and g(x)g(x) grow at the same rate.
Correct Answer: B

Solution:

The exponential function f(x)=exf(x) = e^x grows faster than any polynomial function g(x)=xng(x) = x^n as xx tends to infinity, regardless of the value of nn. This is a fundamental property of exponential functions compared to polynomial functions.

A.

It is continuous but not differentiable at x=0x = 0.

B.

It is discontinuous at x=0x = 0.

C.

It is continuous and differentiable at all real numbers.

D.

It is differentiable but not continuous at x=0x = 0.
Correct Answer: C

Solution:

The function f(x)=exf(x) = e^x is both continuous and differentiable at all real numbers, including x=0x = 0. The derivative of exe^x is exe^x, which is defined everywhere.

A.

Continuous at x=3x = 3

B.

Discontinuous at x=3x = 3

C.

Continuous from the right at x=3x = 3

D.

Continuous from the left at x=3x = 3
Correct Answer: A

Solution:

The function can be simplified to f(x)=x+3f(x) = x + 3 for x3x \neq 3. The limit as xx approaches 3 is limx3(x+3)=6\lim_{x \to 3} (x + 3) = 6. Since the function simplifies to a polynomial, it is continuous at x=3x = 3.

A.

0

B.

1

C.

Infinity

D.

Undefined
Correct Answer: B

Solution:

The limit limx0sinxx=1\lim_{x \to 0} \frac{\sin x}{x} = 1 is a standard result in calculus. It can be derived using L'Hôpital's rule or by recognizing it as a fundamental limit.

A.

sinx\sin x

B.

sinx-\sin x

C.

cosx\cos x

D.

sec2x\sec^2 x
Correct Answer: B

Solution:

The derivative of cosx\cos x is sinx-\sin x.

A.

f(x)=x2f(x) = x^2

B.

f(x)=x3f(x) = x^3

C.

f(x)=10xf(x) = 10^x

D.

f(x)=x10f(x) = x^{10}
Correct Answer: C

Solution:

The function f(x)=10xf(x) = 10^x is an exponential function and grows faster than any polynomial function.

A.

f(x)=x3f(x) = x^3

B.

f(x)=x2f(x) = x^2

C.

f(x)=sin(x)f(x) = \sin(x)

D.

f(x)=cos(x)f(x) = \cos(x)
Correct Answer: B

Solution:

The derivative of f(x)=x2f(x) = x^2 is f(x)=2xf'(x) = 2x. Evaluating at x=0x = 0, we get f(0)=2(0)=0f'(0) = 2(0) = 0.

A.

nxn1nx^{n-1}

B.

n2xn1n^2x^{n-1}

C.

nxn+1nx^{n+1}

D.

xn1x^{n-1}
Correct Answer: A

Solution:

The derivative of f(x)=xnf(x) = x^n with respect to xx is f(x)=nxn1f'(x) = nx^{n-1}, according to the power rule for differentiation.

A.

2xx2+1\frac{2x}{x^2 + 1}

B.

1x2+1\frac{1}{x^2 + 1}

C.

2x2+1\frac{2}{x^2 + 1}

D.

xx2+1\frac{x}{x^2 + 1}
Correct Answer: A

Solution:

Using the chain rule, the derivative of f(x)=ln(x2+1)f(x) = \ln(x^2 + 1) is f(x)=ddx[ln(x2+1)]=1x2+12x=2xx2+1f'(x) = \frac{d}{dx}[\ln(x^2 + 1)] = \frac{1}{x^2 + 1} \cdot 2x = \frac{2x}{x^2 + 1}.

A.

It grows slower than any polynomial function.

B.

It grows at the same rate as polynomial functions.

C.

It grows faster than any polynomial function.

D.

It grows slower than linear functions but faster than quadratic functions.
Correct Answer: C

Solution:

Exponential functions like f(x)=10xf(x) = 10^x grow faster than any polynomial function as xx increases. This is because exponential growth is characterized by a constant multiplicative rate, unlike polynomial growth which is additive.

A.

sec2x\sec^2 x

B.

cosx\cos x

C.

sinx\sin x

D.

sinx-\sin x
Correct Answer: A

Solution:

The derivative of tanx\tan x is sec2x\sec^2 x.

A.

exsin(x)+excos(x)e^x \sin(x) + e^x \cos(x)

B.

excos(x)exsin(x)e^x \cos(x) - e^x \sin(x)

C.

ex(cos(x)+sin(x))e^x (\cos(x) + \sin(x))

D.

ex(cos(x)sin(x))e^x (\cos(x) - \sin(x))
Correct Answer: A

Solution:

Using the product rule, if u(x)=exu(x) = e^x and v(x)=sin(x)v(x) = \sin(x), then h(x)=u(x)v(x)+u(x)v(x)=exsin(x)+excos(x).h'(x) = u'(x)v(x) + u(x)v'(x) = e^x \sin(x) + e^x \cos(x).

A.

It is continuous everywhere.

B.

It is discontinuous at x=0x = 0.

C.

It is only defined for x>0x > 0.

D.

It is not differentiable at x=0x = 0.
Correct Answer: A

Solution:

The function f(x)=cosxf(x) = \cos x is continuous everywhere on the real line.

A.

f(x)=1xf(x) = \frac{1}{x}

B.

f(x)=exf(x) = e^x

C.

f(x)=ln(x)f(x) = \ln(x)

D.

f(x)=1x2f(x) = \frac{1}{x^2}
Correct Answer: B

Solution:

The function f(x)=exf(x) = e^x is continuous for all real numbers, including at x=0x = 0. The function f(x)=1xf(x) = \frac{1}{x} is not defined at x=0x = 0, f(x)=ln(x)f(x) = \ln(x) is not defined for x0x \leq 0, and f(x)=1x2f(x) = \frac{1}{x^2} is not defined at x=0x = 0.

A.

x=1x = 1

B.

x=10x = 10

C.

x=2x = 2

D.

x=3x = 3
Correct Answer: C

Solution:

The exponential function g(x)=10xg(x) = 10^x starts growing faster than the polynomial function f(x)=x10f(x) = x^{10} when x>2x > 2. At x=2x = 2, f(x)=210=1024f(x) = 2^{10} = 1024 and g(x)=102=100g(x) = 10^2 = 100. For x>2x > 2, g(x)g(x) surpasses f(x)f(x) in growth rate.

A.

f(x)=xf(x) = |x|

B.

f(x)=x3f(x) = x^3

C.

f(x)=1xf(x) = \frac{1}{x}

D.

f(x)=tanxf(x) = \tan x
Correct Answer: B

Solution:

The function f(x)=x3f(x) = x^3 is differentiable at all points, including x=0x = 0.

A.

They grow faster than any polynomial function.

B.

They are always periodic.

C.

They are always decreasing.

D.

They have a constant rate of change.
Correct Answer: A

Solution:

Exponential functions grow faster than any polynomial function.

A.

f(x)=1xf(x) = \frac{1}{x}

B.

f(x)=x2f(x) = x^2

C.

f(x)=x3f(x) = x^3

D.

f(x)=exf(x) = e^x
Correct Answer: A

Solution:

The function f(x)=1xf(x) = \frac{1}{x} is not defined at x=0x = 0, hence it is discontinuous at that point.

A.

(,1)(1,)(-\infty, -1) \cup (1, \infty)

B.

(,1)(1,)(-\infty, 1) \cup (1, \infty)

C.

(,1)(1,)(-\infty, -1) \cup (1, \infty)

D.

(1,)(1, \infty)
Correct Answer: A

Solution:

The function f(x)=ln(x21)f(x) = \ln(x^2 - 1) is defined only when x21>0x^2 - 1 > 0, which implies x2>1x^2 > 1. Therefore, x>1x > 1 or x<1x < -1. Thus, the domain of the function is (,1)(1,)(-\infty, -1) \cup (1, \infty).

A.

sin(x)ln(x)+cos(x)x-\sin(x) \ln(x) + \frac{\cos(x)}{x}

B.

sin(x)ln(x)cos(x)x-\sin(x) \ln(x) - \frac{\cos(x)}{x}

C.

sin(x)ln(x)+cos(x)x\sin(x) \ln(x) + \frac{\cos(x)}{x}

D.

sin(x)ln(x)cos(x)x\sin(x) \ln(x) - \frac{\cos(x)}{x}
Correct Answer: A

Solution:

Using the product rule, if u(x)=cos(x)u(x) = \cos(x) and v(x)=ln(x)v(x) = \ln(x), then p(x)=u(x)v(x)+u(x)v(x)=sin(x)ln(x)+cos(x)x.p'(x) = u'(x)v(x) + u(x)v'(x) = -\sin(x) \ln(x) + \frac{\cos(x)}{x}.

A.

cosx\cos x

B.

sinx-\sin x

C.

tanx\tan x

D.

sec2x\sec^2 x
Correct Answer: A

Solution:

The derivative of sinx\sin x is cosx\cos x.

A.

sinx\sin x

B.

sinx-\sin x

C.

cosx\cos x

D.

sec2x\sec^2 x
Correct Answer: B

Solution:

The derivative of f(x)=cosxf(x) = \cos x is f(x)=sinxf'(x) = -\sin x.

A.

f(x)=2xsin(x)+x2cos(x)f'(x) = 2x \sin(x) + x^2 \cos(x)

B.

f(x)=2xcos(x)x2sin(x)f'(x) = 2x \cos(x) - x^2 \sin(x)

C.

f(x)=2xsin(x)x2cos(x)f'(x) = 2x \sin(x) - x^2 \cos(x)

D.

f(x)=2xcos(x)+x2sin(x)f'(x) = 2x \cos(x) + x^2 \sin(x)
Correct Answer: A

Solution:

Using the product rule, f(x)=ddx(x2)sin(x)+x2ddx(sin(x))=2xsin(x)+x2cos(x)f'(x) = \frac{d}{dx}(x^2) \cdot \sin(x) + x^2 \cdot \frac{d}{dx}(\sin(x)) = 2x \sin(x) + x^2 \cos(x).

A.

f(x)=sinxf(x) = \sin x

B.

f(x)=xf(x) = |x|

C.

f(x)=1xf(x) = \frac{1}{x}

D.

f(x)=tanxf(x) = \tan x
Correct Answer: A

Solution:

The function f(x)=sinxf(x) = \sin x is differentiable at every real number.

A.

Continuous at x=0x = 0

B.

Discontinuous at x=0x = 0

C.

Continuous everywhere

D.

Not defined at x=0x = 0
Correct Answer: B

Solution:

The function f(x)f(x) is discontinuous at x=0x = 0 because the left-hand limit and right-hand limit at x=0x = 0 do not equal the function value at x=0x = 0. Specifically, limx0f(x)=1\lim_{x \to 0^-} f(x) = 1, limx0+f(x)=2\lim_{x \to 0^+} f(x) = 2, and f(0)=1f(0) = 1. Since these limits are not equal, the function is discontinuous at x=0x = 0.

A.

1

B.

0

C.

\infty

D.

Undefined
Correct Answer: A

Solution:

The limit limx0sinxx=1\lim_{x \to 0} \frac{\sin x}{x} = 1 is a standard result in calculus.

A.

3x23x^2

B.

x2x^2

C.

3x3x

D.

x3x^3
Correct Answer: A

Solution:

The derivative of x3x^3 is 3x23x^2.

A.

3x2+6x13x^2 + 6x - 1

B.

3x2+6x+13x^2 + 6x + 1

C.

3x26x13x^2 - 6x - 1

D.

3x26x+13x^2 - 6x + 1
Correct Answer: A

Solution:

The derivative of f(x)=x3+3x2x+5f(x) = x^3 + 3x^2 - x + 5 is found by differentiating each term: f(x)=3x2+6x1f'(x) = 3x^2 + 6x - 1.

A.

f(x)=1xf(x) = \frac{1}{x}

B.

f(x)=x2f(x) = x^2

C.

f(x)=1x2f(x) = \frac{1}{x^2}

D.

f(x)=1x1f(x) = \frac{1}{x-1}
Correct Answer: B

Solution:

The function f(x)=x2f(x) = x^2 is a polynomial function, and polynomial functions are continuous at every real number.

A.

Continuous at x=1x = 1

B.

Discontinuous at x=1x = 1

C.

Continuous from the left at x=1x = 1

D.

Continuous from the right at x=1x = 1
Correct Answer: A

Solution:

To check the continuity at x=1x = 1, we need to verify if limx1f(x)=limx1+f(x)=f(1)\lim_{x \to 1^-} f(x) = \lim_{x \to 1^+} f(x) = f(1). We have limx1f(x)=12=1\lim_{x \to 1^-} f(x) = 1^2 = 1 and limx1+f(x)=2(1)+1=3\lim_{x \to 1^+} f(x) = 2(1) + 1 = 3. Since f(1)=1f(1) = 1, the function is not continuous at x=1x = 1.

A.

f(x)=xf(x) = |x|

B.

f(x)=x3f(x) = x^3

C.

f(x)=xf(x) = \sqrt{x}

D.

f(x)=1xf(x) = \frac{1}{x}
Correct Answer: B

Solution:

The function f(x)=x3f(x) = x^3 is differentiable at x=0x = 0 because it is a polynomial function, which is differentiable everywhere. The derivative at x=0x = 0 is f(x)=3x2f'(x) = 3x^2, and f(0)=0f'(0) = 0.

A.

2xx2+1\frac{2x}{x^2 + 1}

B.

xx2+1\frac{x}{x^2 + 1}

C.

1x2+1\frac{1}{x^2 + 1}

D.

2x2+1\frac{2}{x^2 + 1}
Correct Answer: A

Solution:

Using the chain rule, the derivative of f(x)=ln(x2+1)f(x) = \ln(x^2 + 1) is f(x)=ddx[ln(x2+1)]=1x2+1ddx[x2+1]=2xx2+1f'(x) = \frac{d}{dx} [\ln(x^2 + 1)] = \frac{1}{x^2 + 1} \cdot \frac{d}{dx} [x^2 + 1] = \frac{2x}{x^2 + 1}.

A.

It is continuous for all real numbers.

B.

It is continuous for all positive real numbers.

C.

It is continuous for all non-negative real numbers.

D.

It is discontinuous for all real numbers.
Correct Answer: B

Solution:

The natural logarithm function f(x)=ln(x)f(x) = \ln(x) is defined and continuous for all positive real numbers x>0x > 0. It is not defined for x0x \leq 0. Therefore, it is continuous for all positive real numbers.

A.

Yes, f(x)f(x) is continuous at x=2x = 2.

B.

No, f(x)f(x) is not continuous at x=2x = 2.

C.

f(x)f(x) is continuous for x2x \neq 2.

D.

f(x)f(x) is discontinuous for all xx.
Correct Answer: B

Solution:

The function f(x)=x24x2f(x) = \frac{x^2 - 4}{x - 2} simplifies to f(x)=x+2f(x) = x + 2 for x2x \neq 2. However, f(x)f(x) is not defined at x=2x = 2, making it discontinuous at this point.

A.

f(x)=x3f(x) = x^3

B.

f(x)=1xf(x) = \frac{1}{x}

C.

f(x)=cosxf(x) = \cos x

D.

f(x)=exf(x) = e^x
Correct Answer: B

Solution:

The function f(x)=1xf(x) = \frac{1}{x} is not continuous at x=0x = 0 because it is not defined there.

A.

It is continuous at all real numbers.

B.

It is discontinuous at x=πx = \pi.

C.

It is continuous only at integer multiples of π\pi.

D.

It is discontinuous at x=0x = 0.
Correct Answer: A

Solution:

The function f(x)=sin(x)f(x) = \sin(x) is continuous for all real numbers, including at x=0x = 0 and x=πx = \pi. Therefore, it is continuous everywhere.

A.

Continuous at all real numbers

B.

Continuous at x=0x = 0 and x=1x = 1 only

C.

Continuous at x=0x = 0 only

D.

Continuous at x=1x = 1 only
Correct Answer: A

Solution:

Polynomial functions are continuous at all real numbers. Therefore, the function f(x)=x44x3+6x24x+1f(x) = x^4 - 4x^3 + 6x^2 - 4x + 1 is continuous for all real numbers.

A.

nxn1nx^{n-1}

B.

xnx^n

C.

nxn^x

D.

xn+1x^{n+1}
Correct Answer: A

Solution:

The derivative of f(x)=xnf(x) = x^n is f(x)=nxn1f'(x) = nx^{n-1}.

A.

cosx\cos x

B.

sinx-\sin x

C.

tanx\tan x

D.

cosx-\cos x
Correct Answer: A

Solution:

The derivative of sinx\sin x is cosx\cos x.

A.

Continuous at x=0x = 0

B.

Discontinuous at x=0x = 0

C.

Continuous everywhere except at x=0x = 0

D.

Continuous at x=0x = 0 and x=1x = 1
Correct Answer: B

Solution:

To determine the continuity at x=0x = 0, we check if limx0f(x)=f(0)\lim_{x \to 0} f(x) = f(0). Calculating the limit, limx0(x3+3)=3\lim_{x \to 0} (x^3 + 3) = 3. Since f(0)=1f(0) = 1, the limit does not equal the function value at x=0x = 0, hence the function is discontinuous at x=0x = 0.

A.

(,2)(2,)(-\infty, -2) \cup (2, \infty)

B.

(,2)(2,)(-\infty, 2) \cup (2, \infty)

C.

(2,2)(-2, 2)

D.

(0,)(0, \infty)
Correct Answer: A

Solution:

The function g(x)=ln(x24)g(x) = \ln(x^2 - 4) is defined when x24>0x^2 - 4 > 0. Solving the inequality, we get x2>4x^2 > 4, which implies x>2x > 2 or x<2x < -2. Therefore, the domain of g(x)g(x) is (,2)(2,)(-\infty, -2) \cup (2, \infty).

A.

f(x)=exf(x) = e^x

B.

g(x)=xng(x) = x^n

C.

Both grow at the same rate

D.

It depends on the value of nn
Correct Answer: A

Solution:

The exponential function f(x)=exf(x) = e^x grows faster than any polynomial function g(x)=xng(x) = x^n as xx \to \infty. This is because the rate of growth of exponential functions is proportional to their current value, leading to a rapid increase compared to polynomials.

A.

f(x)=2e2xsin(x)+e2xcos(x)f'(x) = 2e^{2x} \sin(x) + e^{2x} \cos(x)

B.

f(x)=2e2xcos(x)+e2xsin(x)f'(x) = 2e^{2x} \cos(x) + e^{2x} \sin(x)

C.

f(x)=2e2xsin(x)e2xcos(x)f'(x) = 2e^{2x} \sin(x) - e^{2x} \cos(x)

D.

f(x)=e2x(2sin(x)+cos(x))f'(x) = e^{2x} (2\sin(x) + \cos(x))
Correct Answer: A

Solution:

Using the product rule, f(x)=ddx(e2x)sin(x)+e2xddx(sin(x))=2e2xsin(x)+e2xcos(x)f'(x) = \frac{d}{dx}(e^{2x}) \cdot \sin(x) + e^{2x} \cdot \frac{d}{dx}(\sin(x)) = 2e^{2x} \sin(x) + e^{2x} \cos(x).

A.

The function is continuous everywhere except at x=0x = 0

B.

The function is continuous for all real numbers

C.

The function is discontinuous only at x=1x = 1

D.

The function is continuous only for x>0x > 0
Correct Answer: A

Solution:

The function f(x)=1xf(x) = \frac{1}{x} is not defined at x=0x = 0, hence it is discontinuous at x=0x = 0. It is continuous for all other real numbers.

A.

The growth of f(x)f(x) is linear.

B.

The growth of f(x)f(x) is exponential.

C.

The growth of f(x)f(x) is polynomial and depends on nn.

D.

The growth of f(x)f(x) is logarithmic.
Correct Answer: C

Solution:

The growth of f(x)=xnf(x) = x^n is polynomial, and it depends on the degree nn. As nn increases, the function grows faster for the same increment in xx.

A.

f(x)=x3f(x) = x^3

B.

g(x)=10xg(x) = 10^x

C.

Both grow at the same rate

D.

Cannot be determined
Correct Answer: B

Solution:

Exponential functions like g(x)=10xg(x) = 10^x grow faster than polynomial functions like f(x)=x3f(x) = x^3 as xx increases.

A.

f(x)=sinxf(x) = \sin x

B.

f(x)=1xf(x) = \frac{1}{x}

C.

f(x)=tanxf(x) = \tan x

D.

f(x)=xf(x) = \sqrt{x}
Correct Answer: A

Solution:

The sine function f(x)=sinxf(x) = \sin x is continuous at every real number. The other functions have points of discontinuity: f(x)=1xf(x) = \frac{1}{x} is discontinuous at x=0x = 0, f(x)=tanxf(x) = \tan x is discontinuous at odd multiples of π2\frac{\pi}{2}, and f(x)=xf(x) = \sqrt{x} is undefined for x<0x < 0.

A.

x=0x = 0

B.

x=1x = 1

C.

x=1x = -1

D.

x=2x = 2
Correct Answer: A

Solution:

The function f(x)=1xf(x) = \frac{1}{x} is not defined at x=0x = 0, hence it is not continuous there.

A.

(,1)(1,)(-\infty, -1) \cup (1, \infty)

B.

(,1)(1,)(-\infty, 1) \cup (1, \infty)

C.

(,1)(1,1)(1,)(-\infty, -1) \cup (-1, 1) \cup (1, \infty)

D.

(1,1)(-1, 1)
Correct Answer: A

Solution:

The function f(x)=ln(x21)f(x) = \ln(x^2 - 1) is defined when x21>0x^2 - 1 > 0, i.e., x>1x > 1 or x<1x < -1. Thus, the domain is (,1)(1,)(-\infty, -1) \cup (1, \infty).

A.

x=0x = 0

B.

x=1x = 1

C.

x=1x = -1

D.

The function is continuous everywhere.
Correct Answer: A

Solution:

The function is discontinuous at x=0x = 0 because the left-hand limit and right-hand limit at this point do not match.

True or False

Correct Answer: True

Solution:

The derivative of sinx\sin x with respect to xx is indeed cosx\cos x, as per standard differentiation rules.

Correct Answer: False

Solution:

The function f(x)=tanxf(x) = \tan x is not continuous at points where cosx=0\cos x = 0, such as x=π2+nπx = \frac{\pi}{2} + n\pi, where nn is an integer.

Correct Answer: True

Solution:

A constant function f(x)=kf(x) = k is continuous at every real number because the limit of f(x)f(x) as xx approaches any real number cc is kk, which equals f(c)f(c).

Correct Answer: True

Solution:

The derivative of sinx\sin x with respect to xx is cosx\cos x, as shown in standard differentiation rules.

Correct Answer: True

Solution:

The derivative of sin(x)\sin(x) is cos(x)\cos(x), which is defined for all real numbers, indicating that sin(x)\sin(x) is differentiable everywhere.

Correct Answer: True

Solution:

Trigonometric functions like f(x)=cosxf(x) = \cos x are continuous at every real number.

Correct Answer: True

Solution:

The derivative of arcsin(x)\arcsin(x) is indeed 11x2\frac{1}{\sqrt{1-x^2}}, which is a standard result in calculus for differentiating inverse trigonometric functions.

Correct Answer: True

Solution:

The derivative of cosx\cos x is indeed sinx-\sin x, as per standard differentiation rules.

Correct Answer: True

Solution:

The function f(x)=x3f(x) = x^3 is a polynomial function, which is continuous at every real number, including x=0x = 0.

Correct Answer: True

Solution:

Polynomial functions, such as f(x)=x3f(x) = x^3, are continuous at every point in their domain, which is all real numbers.

Correct Answer: False

Solution:

While the function f(x)=xnf(x) = x^n grows faster with increasing nn, it is still a polynomial function. There are functions, such as exponential functions, that grow faster than any polynomial function.

Correct Answer: True

Solution:

The derivative of sinx\sin x with respect to xx is cosx\cos x, as given by the standard differentiation rules.

Correct Answer: True

Solution:

For the identity function f(x)=xf(x) = x, the limit as xx approaches any real number cc is cc, which equals f(c)f(c). Hence, it is continuous everywhere.

Correct Answer: False

Solution:

Exponential functions like f(x)=10xf(x) = 10^x grow faster than polynomial functions like f(x)=xnf(x) = x^n for large values of xx.

Correct Answer: True

Solution:

Trigonometric functions like sin(x)\sin(x) are continuous at every real number.

Correct Answer: True

Solution:

The function f(x)=sinxf(x) = \sin x is differentiable at every real number, as it is a standard trigonometric function with a well-defined derivative f(x)=cosxf'(x) = \cos x.

Correct Answer: False

Solution:

Exponential functions like f(x)=10xf(x) = 10^x grow faster than polynomial functions like f(x)=xnf(x) = x^n as xx increases.

Correct Answer: True

Solution:

For a function to be continuous on a closed interval [a,b][a, b], it must be continuous at every point in the interval, including the endpoints aa and bb.

Correct Answer: False

Solution:

The differentiation of inverse trigonometric functions is indeed covered in the study of continuity and differentiability.

Correct Answer: True

Solution:

The derivative of the tangent function is the square of the secant function, so f(x)=sec2(x)f'(x) = \sec^2(x) for f(x)=tan(x)f(x) = \tan(x).

Correct Answer: False

Solution:

The function is not continuous at x=0x = 0 because the left-hand limit and right-hand limit at x=0x = 0 do not match the value of the function at x=0x = 0.

Correct Answer: True

Solution:

If a function is defined only at one point, it is considered continuous there because there are no other points to compare.

Correct Answer: True

Solution:

A constant function f(x)=kf(x) = k is continuous at every real number because limxcf(x)=k=f(c)\lim_{x \to c} f(x) = k = f(c) for any real number cc.

Correct Answer: False

Solution:

The function f(x)=x2f(x) = x^2 is a polynomial and is continuous at all real numbers, including x=0x = 0.

Correct Answer: False

Solution:

The function is not continuous at x=0x = 0 because the limit of the function as xx approaches 0 from the left is 1, and from the right is 2, which do not equal the function's value at x=0x = 0.

Correct Answer: True

Solution:

Polynomial functions like f(x)=x3f(x) = x^3 are continuous at every real number.

Correct Answer: False

Solution:

The function f(x)=1xf(x) = \frac{1}{x} is not defined at x=0x = 0, and therefore it is not continuous at x=0x = 0.

Correct Answer: False

Solution:

The function f(x)=tanxf(x) = \tan x is not defined at x=π2x = \frac{\pi}{2}, and thus it cannot be continuous at this point.

Correct Answer: True

Solution:

Exponential functions grow faster than polynomial functions for large values of xx. As xx increases, 10x10^x will surpass any polynomial function xnx^n.

Correct Answer: True

Solution:

The function ln(x)\ln(x) is continuous and differentiable for all x>0x > 0, as it is defined and smooth in this domain.

Correct Answer: True

Solution:

The identity function f(x)=xf(x) = x is continuous at every real number, as the limit of f(x)f(x) as xx approaches any real number cc is equal to cc, which is f(c)f(c).

Correct Answer: True

Solution:

The identity function f(x)=xf(x) = x is defined and continuous at every real number because for any real number cc, limxcf(x)=c=f(c)\lim_{x \to c} f(x) = c = f(c).

Correct Answer: True

Solution:

Exponential functions like f(x)=exf(x) = e^x grow faster than polynomial functions as xx increases.

Correct Answer: True

Solution:

The derivative of the sine function is the cosine function, so f(x)=cos(x)f'(x) = \cos(x) for f(x)=sin(x)f(x) = \sin(x).

Correct Answer: True

Solution:

The function f(x)=x3f(x) = x^3 is a polynomial, and polynomials are differentiable everywhere on the real line.

Correct Answer: False

Solution:

The function f(x)=tan(x)f(x) = \tan(x) is not continuous at points where cos(x)=0\cos(x) = 0, such as x=π2+kπx = \frac{\pi}{2} + k\pi, where kk is an integer.

Correct Answer: False

Solution:

The identity function f(x)=xf(x) = x is continuous at every real number because f(c)=cf(c) = c for every real number cc, and the limit as xx approaches cc is also cc.

Correct Answer: True

Solution:

Exponential functions like y=10xy = 10^x increase more rapidly than polynomial functions such as y=xny = x^n as xx becomes larger.

Correct Answer: False

Solution:

The function f(x)=tanxf(x) = \tan x is not differentiable at x=π2x = \frac{\pi}{2} because it has a vertical asymptote at this point.

Correct Answer: False

Solution:

Polynomial functions, such as f(x)=x3f(x) = x^3, are continuous everywhere on the real line, including at x=0x = 0.

Correct Answer: False

Solution:

The function tan(x)\tan(x) is not continuous at points where cos(x)=0\cos(x) = 0, i.e., at x=(2n+1)π2x = (2n+1)\frac{\pi}{2} for any integer nn, due to vertical asymptotes.

Correct Answer: True

Solution:

Exponential functions like y=10xy = 10^x grow faster than polynomial functions like y=x4y = x^4 as xx increases.

Correct Answer: True

Solution:

Exponential functions like f(x)=exf(x) = e^x are continuous at every real number.

Correct Answer: True

Solution:

If a function is defined only at one point, it is continuous there by definition, as there are no other points to consider for limits.